The molar mass of Na = 22.99 g/mol, Cl = 35.45 g/mol
Total mass of reactants = 2(22.99) + 2(35.45) = 45.98 + 70.9 = 116.88 g
Since the reaction produces 2 moles of NaCl, the total mass of the products will be:
2 * (22.99 + 35.45) = 2 * 58.44 = 116.88 g
Therefore, the total mass of the products will be 116.88 amu.
So the correct answer is: 116.88 amu
Sodium reacts with chionne to form the compound sodium chlonde, or salt. The chemical formula below shows how the two elements combine into a compound
2Na + C*l_{2} 2NaCl
If the fotal mass of the reactants is 58:44 amu, what will be the total mass of the products?
(1 point)
60 amu
116 88 am
58:44 amu
29.22 amu
1 answer
1 answer