Use the table to answer the question.

Number of White Balls Selected Number of Red Balls Selected
Bowl A 45 55
Bowl B 60 40
Bowls A and B contain a number of white and red balls. Clark repeatedly selected a ball from both bowls and recorded the
results in a table. If there are 500 balls in Bowl B, what is the estimated difference in the expected number of white and red
balls in Bowl B?
(1 point)
200
100
300
50

1 answer

The total number of balls selected from Bowl B is 60 (white balls) + 40 (red balls) = 100 balls.

The percentage of white balls in Bowl B is 60/100 = 0.6, or 60%.

Given that Bowl B contains 500 balls, the estimated number of white balls in Bowl B is 500 * 0.6 = 300 white balls.

Similarly, the estimated number of red balls in Bowl B is 500 * 0.4 = 200 red balls.

Therefore, the estimated difference in the expected number of white and red balls in Bowl B is 300 - 200 = 100.

Therefore, the answer is 100, which is the estimated difference in the expected number of white and red balls in Bowl B.