The maximum height of the ball can be found by analyzing the function h(t) = 104t - 16t^2.
To find the maximum height, we need to find the vertex of the parabolic function represented by h(t) = -16t^2 + 104t. The vertex of a parabola in the form y = ax^2 + bx + c is given by the formula x = -b / (2a).
In this case, a = -16 and b = 104. Plugging into the formula, we get t = -104 / (2*(-16)) = -104 / -32 = 3.25.
Therefore, the maximum height occurs at t = 3.25 seconds. We can find the maximum height by plugging this time back into the function h(t):
h(3.25) = 104(3.25) - 16(3.25)^2 = 337 feet
So, the maximum height that the ball reaches is 337 feet.
A ball is thrown vertically upward. After t seconds, its height h (in feet) is given by the function h (t) = 104t- 16t^2 . What is the maximum height that the ball
Do not round
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