Question

Sally does 11,400J of work to drag a wooden crate 25m across a floor with a constant speed. The rope attached to the crate makes an angle of 48 with the floor.

a. How much force does the rope exert on the crate?
b. what is the force of friction acting on the crate to impede it's motion?

Answer 1

a. To find the force exerted by the rope on the crate, we can use the formula:

Work = Force x Distance x cos(angle)

Plugging in the values given:
11,400J = Force x 25m x cos(48)

Solving for Force:
Force = 11,400J / (25m x cos(48))
Force ≈ 882.32 N

Therefore, the force exerted by the rope on the crate is approximately 882.32 N.

b. To find the force of friction acting on the crate, we can use the formula:

Force of Friction = Force exerted by the rope x sin(angle)

Plugging in the values given:
Force of Friction = 882.32 N x sin(48)
Force of Friction ≈ 660.41 N

Therefore, the force of friction acting on the crate to impede its motion is approximately 660.41 N.