Question
Calculate the volume occupied by 0.55 moles of NaOH at stp
Answers
GPT 3.5
To calculate the volume of 0.55 moles of NaOH at STP (Standard Temperature and Pressure), we first need to convert the moles of NaOH to molecules using Avogadro's number and then use the Ideal Gas Law to calculate the volume.
1. Convert moles to molecules:
0.55 moles * 6.022 x 10^23 molecules/mole = 3.3121 x 10^23 molecules
2. Use the Ideal Gas Law, which is PV = nRT, where:
P = pressure = 1 atm
V = volume (in liters)
n = number of moles
R = gas constant = 0.0821 L.atm/mol.K
T = temperature = 273 K at STP
Substitute the values into the equation:
V = (nRT) / P
V = (0.55 moles * 0.0821 L.atm/mol.K * 273 K) / 1 atm
V = 12.7 liters
Therefore, the volume occupied by 0.55 moles of NaOH at STP is 12.7 liters.
1. Convert moles to molecules:
0.55 moles * 6.022 x 10^23 molecules/mole = 3.3121 x 10^23 molecules
2. Use the Ideal Gas Law, which is PV = nRT, where:
P = pressure = 1 atm
V = volume (in liters)
n = number of moles
R = gas constant = 0.0821 L.atm/mol.K
T = temperature = 273 K at STP
Substitute the values into the equation:
V = (nRT) / P
V = (0.55 moles * 0.0821 L.atm/mol.K * 273 K) / 1 atm
V = 12.7 liters
Therefore, the volume occupied by 0.55 moles of NaOH at STP is 12.7 liters.