Asked by philippa
A ship sailed on a bearing 140 degrees. It was then 90 km south of its orignal position.
a) draw a diagram to show the ship's journey
b) how far east of its original position is it?
what ratio would i need? (sine,cosine or tangent)
i know that all trig questions have a right-angled triangle but where would i put the angle(140) and the line(9)
thanks in advance :)
a) draw a diagram to show the ship's journey
b) how far east of its original position is it?
what ratio would i need? (sine,cosine or tangent)
i know that all trig questions have a right-angled triangle but where would i put the angle(140) and the line(9)
thanks in advance :)
Answers
Answered by
MathMate
A bearing of 140 degrees is measured clockwise from north, and is generally called azimuth in North America.
This translates to S40E in general terms, or (90-140)=-50 degrees in trigonometry (4th quadrant, cosine >0, sine <0)
If the ship was 90 km south of its original position, then
D sin(-50°)=-90 km
from which you can calculate D, the distance travelled in the direction of 140° in km.
This translates to S40E in general terms, or (90-140)=-50 degrees in trigonometry (4th quadrant, cosine >0, sine <0)
If the ship was 90 km south of its original position, then
D sin(-50°)=-90 km
from which you can calculate D, the distance travelled in the direction of 140° in km.
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