Let X be a random variable with the standard normal distribution. Find: P(X > 1.23)

Question

0.8907


0.1093


0.9032


0.8849


0.0956

Answer 1

0.1093

We can find this by looking up the z-score of 1.23 in the standard normal distribution table. The z-score for 1.23 is approximately 0.8907.

Since we want to find P(X > 1.23), we need to find the area to the right of 1.23. This is equivalent to 1 - P(X < 1.23), which is 1 - 0.8907 = 0.1093.

Therefore, the probability that X is greater than 1.23 is 0.1093.