To find out when the ball will hit the ground, we set h (the height) equal to 0 and solve for t.
0 = -16t^2 + 46t + 6
You can factor this equation or use the quadratic formula to solve for t. Using the quadratic formula:
t = (-46 ± √(46^2 - 4(-16)(6))) / (2(-16))
t = (-46 ± √(2116 + 384)) / -32
t = (-46 ± √2500) / -32
t = (-46 ± 50) / -32
t = 4 or t = -6/8
Since time can't be negative for this problem, the ball will hit the ground after 4 seconds, so the answer is B. 4.
A ball is thrown into the air with an initial upward velocity of 46 ft/s. Its height (h) in feet after t seconds is given by the function h=-16t^2 +46t +6. After how many seconds will the ball hit the ground?
A. 3
B. 4
C. 5
D. 6
1 answer