To solve this system of equations using elimination with multiplication, we need to multiply one or both equations by a constant in order to make the coefficients of one of the variables the same.
First, let's multiply the second equation by 2 to make the coefficients of x the same:
- 2x + 4y = 30
2(- 2x + 4y) = 2(30)
- 4x + 8y = 60
Now our system of equations becomes:
4x - 6y = - 48
- 4x + 8y = 60
Next, we add the two equations together to eliminate the x variable:
(4x - 6y) + (- 4x + 8y) = -48 + 60
2y = 12
y = 6
Now that we have the value of y, we can substitute it back into one of the original equations to solve for x. Let's use the first equation:
4x - 6(6) = -48
4x - 36 = -48
4x = -12
x = -3
Therefore, the solution to the system of equations is x = -3, y = 6.
Solve the system of two equations using elimination with multiplication.
4x - 6y = - 48
- 2x + 4y = 30 (1 point)
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