How do you solve for x in (3/4)x^2-12? I'm not sure how to factor this, unless there's another way to solve.

Answer 1

to "solve" you need an equation.
You don't have an equation.

Are you factoring (3/4)x^2-12 ?

if so, then

(3/4)x^2-12
= (3/4)(x^2 - 16)
= (3/4)(x-4)(x+4)