Asked by Anonymous
Jane, looking for Tarzan, is running at top speed (4.3 m/s) and grabs a vine hanging vertically from a tall tree in the jungle. How high can she swing upward?
Answers
Answered by
Shane
v=4.3
g=9.8
GPE=KE
mgh=(1/2)mv^2
mass cancels out so;
gh=(1/2)v^2
plug in your values and you should get the right answer
g=9.8
GPE=KE
mgh=(1/2)mv^2
mass cancels out so;
gh=(1/2)v^2
plug in your values and you should get the right answer
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