From the balanced chemical equation, we can see that the stoichiometry of the reaction is 2:25 for C8H18:O2, and 2:16 for C8H18:CO2.
Therefore, if 2.00 moles of C8H18 react, the theoretical yield, in moles, of CO2 can be calculated as follows:
2.00 moles C8H18 x (16 moles CO2 / 2 moles C8H18) = 16.00 moles CO2
Therefore, the theoretical yield of CO2 from the reaction of 2.00 moles of C8H18 is 16.00 moles.
Give the theoretical yield, in moles, of CO2 from the reaction of 2.00 moles of C8H18 with 2.00 moles of O2.
2 C8H18 + 25 O2→ 16 CO2 + 18 H2O
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