The Walker and Baldwin families ordered lunch at the refreshment stand at the basketball game. The Walker family ordered 4 hot dogs and 3 cheeseburgers and paid $23.75. The Baldwin family ordered 6 hots dogs and 2 cheeseburgers and paid $25. Write a system of equations using h for hot dogs and for cheeseburgers.(1 point)

Question

Responses

A. 7c = 23.75 and 8h = 25

B. h + c = 23.75
and h + c = 25

C. 4h − 3c = 23.75
and 6h − 2c = 25

D. 4h + 3c = 23.75
and 6h + 2c = 25

Question 2
What are the prices of a hot dog and a cheeseburger?
$4.25 $2.00 $5.00 $2.75
Cheeseburger . . . .

Hot dog . . . .

Answer 1

Responses

A. Cheeseburger $5.00 and hot dog $2.75

B. Cheeseburger $4.25 and hot dog $2.00

C. Cheeseburger $2.00 and hot dog $4.25

D. Cheeseburger $2.75 and hot dog $5.00

Answer 2

I don't get this

Answer 3

I apologize for the confusion. Let's break it down further.

From the information given, we can write two equations:

1. For the Walker family, they ordered 4 hot dogs (4h) and 3 cheeseburgers (3c) for a total cost of $23.75:
4h + 3c = 23.75

2. For the Baldwin family, they ordered 6 hot dogs (6h) and 2 cheeseburgers (2c) for a total cost of $25:
6h + 2c = 25

Now, to find the prices of a hot dog (h) and a cheeseburger (c), we need to solve this system of equations. The correct system of equations that we established in the first question is:

4h + 3c = 23.75
6h + 2c = 25

Solving this system of equations will give us the values of h and c, which represent the prices of a hot dog and a cheeseburger. Let's solve it step-by-step:

From equation 1:
4h + 3c = 23.75
3c = 23.75 - 4h
c = (23.75 - 4h) / 3

From equation 2:
6h + 2c = 25
2c = 25 - 6h
c = (25 - 6h) / 2

Now that we have expressions for c, we can set these two equal to find the price of c:
(23.75 - 4h) / 3 = (25 - 6h) / 2

By solving this equation, you'll find the value of h (price of a hot dog) and c (price of a cheeseburger).