Surface Area Unit Test

15 of 1615 of 16 Items

Question
Olga is making presents for her teachers and needs to wrap them. She places the gifts in a right circular cylinder with a height of 12 inches and diameter of 6 inches. How much wrapping paper does she need for each gift she is going to wrap? Use 3.14 for π .(1 point)
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1 answer

To find the surface area of the cylinder, we need to calculate the lateral surface area (wrapping paper needed for the sides) and the surface area of the two circular ends.

1. Lateral Surface Area:
The formula for the lateral surface area of a cylinder is: 2πrh, where r is the radius and h is the height.
Given that the diameter is 6 inches, the radius (r) is half of the diameter, so r = 6 / 2 = 3 inches.
Now we can calculate the lateral surface area:
2 * 3.14 * 3 * 12 = 226.08 square inches

2. Surface Area of the Circular Ends:
The formula for the surface area of a circle is: πr^2, where r is the radius.
The radius is 3 inches, so we can calculate the area of one circular end:
3.14 * 3^2 = 28.26 square inches
Since there are two ends, the total surface area for both ends is:
2 * 28.26 = 56.52 square inches

3. Total Wrapping Paper Needed:
The total wrapping paper needed is the sum of the lateral surface area and the surface area of the two ends:
226.08 + 56.52 = 282.6 square inches

Therefore, Olga will need 282.6 square inches of wrapping paper for each gift she wraps.
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