Asked by BELLA
                I know the answers, but am having trouble writing the equation.  Their ages are 17 and 8.5, and 14.5
Can I get help with the equaiton?
The sum of the ages of Sonia, Collin, and Ana is 40. Sonia is twice as old as Ana. Ana is 6 years younger than Collin. How old are they? Write and solve an algebra equation.(may have decimals)
            
        Can I get help with the equaiton?
The sum of the ages of Sonia, Collin, and Ana is 40. Sonia is twice as old as Ana. Ana is 6 years younger than Collin. How old are they? Write and solve an algebra equation.(may have decimals)
Answers
                    Answered by
            MathMate
            
    It's odd, most of the time, questions regarding ages are integer numbers.  I agree with your answer, here's how you could have done it.
Let A,S, and C represent the age of each person.
The sum of the ages of Sonia, Collin, and Ana is 40, so
S+C+A=40......(1)
Sonia is twice as old as Ana, so
S=2A.......(2)
Ana is 6 years younger than Collin, so
C=A+6......(3)
Notice how S and C both have been expressed in terms of A.
Now substitute (2) and (3) in (1) to get
S+C+A=40
(2A)+(A+6)+A = 40
4A+6=40
4A=34
A=8.5
The rest is just substituting A=8.5 in equations (2) and (3).
Hope that helps.
    
Let A,S, and C represent the age of each person.
The sum of the ages of Sonia, Collin, and Ana is 40, so
S+C+A=40......(1)
Sonia is twice as old as Ana, so
S=2A.......(2)
Ana is 6 years younger than Collin, so
C=A+6......(3)
Notice how S and C both have been expressed in terms of A.
Now substitute (2) and (3) in (1) to get
S+C+A=40
(2A)+(A+6)+A = 40
4A+6=40
4A=34
A=8.5
The rest is just substituting A=8.5 in equations (2) and (3).
Hope that helps.
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