First, we need to find the lateral surface area of the cylinder.
Lateral surface area of a cylinder = 2πrh
Given that the radius (r) is 3 feet, and the lateral surface area is 395.64 feet^2, we can plug in the values to find the height (h).
395.64 = 2(3.14)(3)h
395.64 = 18.84h
h = 395.64 / 18.84
h = 21 feet
Therefore, the height of the net diagram of the right circular cylinder is 21 feet.
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Question
Use the image to answer the question.
An illustration shows a rectangle of unknown height with a circle of radius 3 feet attached to its top left and a circle of radius 3 feet attached to its bottom right.
If the surface area of the net diagram of the right circular cylinder is 395.64 feet2 , find the height of the net diagram. Use 3.14 for π .
4 answers
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Let's recheck the calculations.
Using the formula for the lateral surface area of a cylinder:
Lateral surface area = 2πrh
Given that the radius (r) is 3 feet and the lateral surface area is 395.64 feet^2, we can plug in the values:
395.64 = 2(3.14)(3)h
395.64 = 18.84h
h = 395.64 / 18.84
h ≈ 20.98 feet
Therefore, the height of the net diagram of the right circular cylinder is approximately 20.98 feet.
Using the formula for the lateral surface area of a cylinder:
Lateral surface area = 2πrh
Given that the radius (r) is 3 feet and the lateral surface area is 395.64 feet^2, we can plug in the values:
395.64 = 2(3.14)(3)h
395.64 = 18.84h
h = 395.64 / 18.84
h ≈ 20.98 feet
Therefore, the height of the net diagram of the right circular cylinder is approximately 20.98 feet.
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