In order to determine the equation of a line parallel to y = 3x + 4 that passes through the point (1,1), we need to find a line with the same slope as y = 3x + 4.
The slope-intercept form of a linear equation is y = mx + b, where m represents the slope and b represents the y-intercept.
The slope of y = 3x + 4 is 3, so a line parallel to it must also have a slope of 3.
Using the point-slope form of a linear equation (y - y1 = m(x - x1), where (x1, y1) is the point), we can plug in the slope value of 3 and the coordinates of point (1,1):
y - 1 = 3(x - 1)
y - 1 = 3x - 3
y = 3x - 2
Therefore, the equation of the line that is parallel to y = 3x + 4 and passes through the point (1,1) is y = 3x - 2.
The correct answer choice is y = 3x - 2.
What is an equation of the line that is parallel to y = 3x + 4 and passes through the point (1,1)?
Answer choices
y = 3x
y = 3x + 2
y = 3x - 1
y = 3x - 2
1 answer
1 answer