The cost of a piece of candy is described by the equation y = $0.35x What is the cost of one piece of candy?
7 answers
The cost of one piece of candy is $0.35.
Examine these equations
1.y=5x-4
2.=-2x+3
3.y=3x+1
4.2y=6x+2
5.y-5x=+2
6.y-4x+1=0
7.y=5x
Complete steps a through E! To determine which pair of equations form a system with one solution. No solution or infinite solutions.
Be sure to solve each equation and make sure it is y =.Mx+b format
1.y=5x-4
2.=-2x+3
3.y=3x+1
4.2y=6x+2
5.y-5x=+2
6.y-4x+1=0
7.y=5x
Complete steps a through E! To determine which pair of equations form a system with one solution. No solution or infinite solutions.
Be sure to solve each equation and make sure it is y =.Mx+b format
a) Solve equation 1 for y:
y = 5x - 4
b) Solve equation 2 for y:
y = -2x + 3
c) Solve equation 3 for y:
y = 3x + 1
d) Solve equation 4 for y:
2y = 6x + 2
Divide by 2 on both sides:
y = 3x + 1
e) Solve equation 5 for y:
y - 5x = 2
Add 5x to both sides:
y = 5x + 2
f) Solve equation 6 for y:
y - 4x + 1 = 0
Subtract 1 and add 4x to both sides:
y = 4x - 1
g) Solve equation 7 for y:
y = 5x
From these equations, we can see that equations 1, 2, and 5 are in slope-intercept form (y = mx + b). Let's analyze them:
Equation 1: y = 5x - 4
- The slope is 5
- The y-intercept is -4
Equation 2: y = -2x + 3
- The slope is -2
- The y-intercept is 3
Equation 5: y = 5x + 2
- The slope is 5
- The y-intercept is 2
Since equations 1, 2, and 5 all have different slopes, they will form a system with one solution.
y = 5x - 4
b) Solve equation 2 for y:
y = -2x + 3
c) Solve equation 3 for y:
y = 3x + 1
d) Solve equation 4 for y:
2y = 6x + 2
Divide by 2 on both sides:
y = 3x + 1
e) Solve equation 5 for y:
y - 5x = 2
Add 5x to both sides:
y = 5x + 2
f) Solve equation 6 for y:
y - 4x + 1 = 0
Subtract 1 and add 4x to both sides:
y = 4x - 1
g) Solve equation 7 for y:
y = 5x
From these equations, we can see that equations 1, 2, and 5 are in slope-intercept form (y = mx + b). Let's analyze them:
Equation 1: y = 5x - 4
- The slope is 5
- The y-intercept is -4
Equation 2: y = -2x + 3
- The slope is -2
- The y-intercept is 3
Equation 5: y = 5x + 2
- The slope is 5
- The y-intercept is 2
Since equations 1, 2, and 5 all have different slopes, they will form a system with one solution.
O k but can you put solution no solution or infinite solutions for each Question.
Sure, here is the analysis with whether the pair of equations form a system with one solution, no solution, or infinite solutions:
1. Equation 1: y = 5x - 4
Equation 2: y = -2x + 3
→ One solution
2. Equation 2: y = -2x + 3
Equation 5: y = 5x + 2
→ One solution
3. Equation 1: y = 5x - 4
Equation 5: y = 5x + 2
→ No solution
Each pair of equations has been analyzed, and the results are based on the relationship between the slopes of the lines represented by the equations.
1. Equation 1: y = 5x - 4
Equation 2: y = -2x + 3
→ One solution
2. Equation 2: y = -2x + 3
Equation 5: y = 5x + 2
→ One solution
3. Equation 1: y = 5x - 4
Equation 5: y = 5x + 2
→ No solution
Each pair of equations has been analyzed, and the results are based on the relationship between the slopes of the lines represented by the equations.
And four through seven
Sure, here is the analysis for equations 4 through 7:
4. Equation 3: y = 3x + 1
Equation 4: 2y = 6x + 2 -> y = 3x + 1
→ Infinite solutions
5. Equation 4: 2y = 6x + 2 -> y = 3x + 1
Equation 5: y = 5x + 2
-> No solution
6. Equation 5: y = 5x + 2
Equation 6: y = 4x - 1
→ One solution
7. Equation 7: y = 5x
Equation 6: y = 4x - 1
→ One solution
These analyses consider the slopes of the lines represented by the equations to determine whether the system has one solution, no solution, or infinite solutions.
4. Equation 3: y = 3x + 1
Equation 4: 2y = 6x + 2 -> y = 3x + 1
→ Infinite solutions
5. Equation 4: 2y = 6x + 2 -> y = 3x + 1
Equation 5: y = 5x + 2
-> No solution
6. Equation 5: y = 5x + 2
Equation 6: y = 4x - 1
→ One solution
7. Equation 7: y = 5x
Equation 6: y = 4x - 1
→ One solution
These analyses consider the slopes of the lines represented by the equations to determine whether the system has one solution, no solution, or infinite solutions.