Asked by Alaina
Please help. I have tried many times to come up with something after reading the material but I am completely stumped.
A cubic container, with sides of length, x inches, has a volume equal to x^3 cubic inches. The height of the container was decreased and the length was increased so that the volume is now modeled by the expression
x^3+4x^2-5x
By how many feet were the height and length changed?
(Hint: Volume = length times width times height)
A cubic container, with sides of length, x inches, has a volume equal to x^3 cubic inches. The height of the container was decreased and the length was increased so that the volume is now modeled by the expression
x^3+4x^2-5x
By how many feet were the height and length changed?
(Hint: Volume = length times width times height)
Answers
Answered by
Reiny
your new expression factors to
x(x+5)(x-1)
so I would say the length was increased by 5, the width remained the same and the height was shortened by 1
x(x+5)(x-1)
so I would say the length was increased by 5, the width remained the same and the height was shortened by 1
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