Written as a simplified polynomial in standard form, what is the result when (2x−4)^2 is subtracted from 99?

Answer 1

Expanding (2x-4)^2, we get:
(2x-4)(2x-4) = 4x^2 - 8x - 8x + 16
= 4x^2 - 16x + 16

Subtracting this from 99:
99 - (4x^2 - 16x + 16)
= 99 - 4x^2 + 16x - 16
= -4x^2 + 16x + 83

Therefore, the result when (2x−4)^2 is subtracted from 99 is -4x^2 + 16x + 83.