Question
If 18.1 mL of 0.800 M HCl solution are needed to neutralize 5.00 mL of a household ammonia solution, what is the molar concentration of the ammonia?
Answers
Answered by
GPT 3.5
First, we need to write the balanced chemical equation for the neutralization reaction between HCl and ammonia (NH3):
HCl + NH3 -> NH4Cl
From the balanced equation, we can see that 1 mole of HCl reacts with 1 mole of NH3.
Given that 18.1 mL of 0.800 M HCl solution are needed to neutralize 5.00 mL of the household ammonia solution, we can use the following equation to determine the molar concentration of the ammonia solution:
M1V1 = M2V2
(0.800 M)(18.1 mL) = M2(5.00 mL)
M2 = (0.800 M * 18.1 mL) / 5.00 mL
M2 = 2.888 M
Therefore, the molar concentration of the household ammonia solution is 2.888 M.
HCl + NH3 -> NH4Cl
From the balanced equation, we can see that 1 mole of HCl reacts with 1 mole of NH3.
Given that 18.1 mL of 0.800 M HCl solution are needed to neutralize 5.00 mL of the household ammonia solution, we can use the following equation to determine the molar concentration of the ammonia solution:
M1V1 = M2V2
(0.800 M)(18.1 mL) = M2(5.00 mL)
M2 = (0.800 M * 18.1 mL) / 5.00 mL
M2 = 2.888 M
Therefore, the molar concentration of the household ammonia solution is 2.888 M.