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1. It has been suggested that rotating cylinders about 11 mi long and 5.2 mi in diameter be placed in space and used as colonie...Asked by jb
It has been suggested that rotating cylinders about 12 mi long and 5.4 mi in diameter be placed in space and used as colonies. What angular speed must such a cylinder have so that the centripetal acceleration at its surface equals the free-fall acceleration on Earth?
Answers
Answered by
drwls
R = 2.7 miles = 1.426*10^4 ft
R w^2 = g = 32.2 ft^2/s
Solve for the angular speed, w, in radians/s
w = sqrt (g/R) = sqrt (32.2/1.4264*10^4)
= sqrt 2.259*10^-3 = 4.74*10^-2 rad/s
R w^2 = g = 32.2 ft^2/s
Solve for the angular speed, w, in radians/s
w = sqrt (g/R) = sqrt (32.2/1.4264*10^4)
= sqrt 2.259*10^-3 = 4.74*10^-2 rad/s
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