Let's represent the total cost of the first option as 10x + 20, where x is the number of tickets purchased. The total cost of the second option can be represented as 5y + 50, where y is the number of tickets purchased.
To find out when both options are the same price, we need to set the two equations equal to each other:
10x + 20 = 5y + 50
Subtract 20 from both sides:
10x = 5y + 30
Divide by 5:
2x = y + 6
Now we can substitute y for 2x in the second option equation and solve for x:
5(2x) + 50 = 10x + 20
10x + 50 = 10x + 20
50 = 20
This equation has no solution, meaning that the two options will never be the same price.
A movie theater offers two options for memberships. The first option costs 10$ per ticket but an initial fee of 20$ the second option 5$ per ticket but a initial fee of 50$ after how many tickets are both options the same price
1 answer