The numerator would be calculated by finding the number of ways to choose 3 out of the 4 4's in the deck, multiplied by the number of ways to choose the remaining 2 cards from the 48 cards that are not 4's.
There are ${4 \choose 3} = 4$ ways to choose 3 out of the 4 4's, and ${48 \choose 2} = 1128$ ways to choose the remaining 2 cards from the 48 non-4 cards.
Therefore, the numerator would be $4 \times 1128 = 4512$.
What would be the numerator of being dealt exactly three 4's in a 5-card hand from a standard 52-card deck
1 answer