Question

The pressure exerted by 1.3 mol of gas in a 13 L flask at 22 °C is ________ kPa.

Answer 1

To find the pressure exerted by the gas, we can use the ideal gas law equation:

PV = nRT

Where:
P = pressure
V = volume (13 L)
n = number of moles of gas (1.3 mol)
R = ideal gas constant (8.31 J/mol*K)
T = temperature (22 °C + 273.15 = 295.15 K)

Plugging in the values:

P * 13 = 1.3 * 8.31 * 295.15

P * 13 = 3212.557095 kPa

P = 3212.557095 / 13

P = 247.12 kPa

Therefore, the pressure exerted by 1.3 mol of gas in a 13 L flask at 22 °C is 247.12 kPa.