A contractors building a new house. She creates a map with the coordinates a(6,12),b(6,-6),c(-4,-6)d(-4,12). Each unit on the coordinate plane represents 1 yard what is the perimeter of the outside of the house?

Answer 1

To find the perimeter of the outside of the house, we need to calculate the sum of the lengths of all four sides of the house.

Using the coordinates given, we can calculate the lengths of each side:

Side AB: Distance between points A(6,12) and B(6,-6)
AB = |12 - (-6)| = 18

Side BC: Distance between points B(6,-6) and C(-4,-6)
BC = |6 - (-4)| = 10

Side CD: Distance between points C(-4,-6) and D(-4,12)
CD = |(-6) - 12| = 18

Side DA: Distance between points D(-4,12) and A(6,12)
DA = |(-4) - 6| = 10

Now, we can calculate the perimeter by adding the lengths of all four sides:

Perimeter = AB + BC + CD + DA
Perimeter = 18 + 10 + 18 + 10
Perimeter = 56 yards

Therefore, the perimeter of the outside of the house is 56 yards.