Question
In which of the given sets of numbers are all the numbers solutions of 18+2x≥36 ?(1 point)
9, 8, 7, 6
9, 10, 11, 12
8, 7, 6
0, 3, 9, 12
9, 8, 7, 6
9, 10, 11, 12
8, 7, 6
0, 3, 9, 12
Answers
Answer
are u sure
Answered by
GPT 3.5
The correct set of numbers is: 0, 3, 9, 12
Plugging each of these numbers into the inequality:
For 0: 18 + 2*(0) = 18 which is not greater than or equal to 36
For 3: 18 + 2*(3) = 24 which is not greater than or equal to 36
For 9: 18 + 2*(9) = 36 which is equal to 36
For 12: 18 + 2*(12) = 42 which is greater than or equal to 36
Therefore, the set of numbers that are all solutions to 18 + 2x ≥ 36 is 0, 3, 9, 12.
Plugging each of these numbers into the inequality:
For 0: 18 + 2*(0) = 18 which is not greater than or equal to 36
For 3: 18 + 2*(3) = 24 which is not greater than or equal to 36
For 9: 18 + 2*(9) = 36 which is equal to 36
For 12: 18 + 2*(12) = 42 which is greater than or equal to 36
Therefore, the set of numbers that are all solutions to 18 + 2x ≥ 36 is 0, 3, 9, 12.
Answered by
GPT 3.5
Apologies for the error in my previous response. Let's go through each set of numbers to determine which set has numbers that are all solutions to 18 + 2x ≥ 36.
1. Set: 9, 8, 7, 6
Plugging 9 into the inequality: 18 + 2*(9) = 18 + 18 = 36 which is equal to 36
Plugging 8 into the inequality: 18 + 2*(8) = 18 + 16 = 34 which is not greater than or equal to 36
Plugging 7 into the inequality: 18 + 2*(7) = 18 + 14 = 32 which is not greater than or equal to 36
Plugging 6 into the inequality: 18 + 2*(6) = 18 + 12 = 30 which is not greater than or equal to 36
Since there are numbers in this set that do not satisfy the inequality, this set is not the correct one.
2. Set: 9, 10, 11, 12
Each number in this set will result in the left-hand side of the inequality being smaller than 36. Therefore, this set is not the correct one.
3. Set: 8, 7, 6
Plugging in 8, 7, and 6 into the inequality will result in values less than 36, so this set is not the correct one.
4. Set: 0, 3, 9, 12
As previously mentioned, when we plug in 9 and 12 into the inequality, we get values of 36 and above.
Therefore, the correct set of numbers where all the numbers are solutions of 18 + 2x ≥ 36 is 0, 3, 9, 12. Thank you for pointing out the mistake earlier.
1. Set: 9, 8, 7, 6
Plugging 9 into the inequality: 18 + 2*(9) = 18 + 18 = 36 which is equal to 36
Plugging 8 into the inequality: 18 + 2*(8) = 18 + 16 = 34 which is not greater than or equal to 36
Plugging 7 into the inequality: 18 + 2*(7) = 18 + 14 = 32 which is not greater than or equal to 36
Plugging 6 into the inequality: 18 + 2*(6) = 18 + 12 = 30 which is not greater than or equal to 36
Since there are numbers in this set that do not satisfy the inequality, this set is not the correct one.
2. Set: 9, 10, 11, 12
Each number in this set will result in the left-hand side of the inequality being smaller than 36. Therefore, this set is not the correct one.
3. Set: 8, 7, 6
Plugging in 8, 7, and 6 into the inequality will result in values less than 36, so this set is not the correct one.
4. Set: 0, 3, 9, 12
As previously mentioned, when we plug in 9 and 12 into the inequality, we get values of 36 and above.
Therefore, the correct set of numbers where all the numbers are solutions of 18 + 2x ≥ 36 is 0, 3, 9, 12. Thank you for pointing out the mistake earlier.
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