Question

Using the formula P total = m_{1}*v_{1} + m_{2}*v_{2} , what is the momentum of a system where Object A has a mass of 5.0 kg and a velocity of 120km / h * r east and Object B has a mass of 7.0 kg and velocity of 110km / h * r west? Let the east velocity be positive. (1 point)

- 170kgkm / h * r

242kgkm / h * r

8kgkm / h * r

1, 370kgkm / h * r

Answer 1

To solve this problem, we need to calculate the momentum of each object individually and then add them together to find the total momentum of the system.

Object A:
m1 = 5.0 kg
v1 = 120 km/h (east, positive direction)

Momentum of Object A:
P1 = m1 * v1
P1 = 5.0 kg * 120 km/h = 600 kg km/h (east, positive direction)

Object B:
m2 = 7.0 kg
v2 = 110 km/h (west, negative direction)

Momentum of Object B:
P2 = m2 * v2
P2 = 7.0 kg * (-110 km/h) = -770 kg km/h (west, negative direction)

Total Momentum of the System:
Ptotal = P1 + P2
Ptotal = 600 kg km/h + (-770 kg km/h)
Ptotal = -170 kg km/h

Therefore, the total momentum of the system where Object A has a mass of 5.0 kg and velocity of 120 km/h east and Object B has a mass of 7.0 kg and velocity of 110 km/h west is -170 kg km/h. (east direction is positive and west direction is negative)