If 1.000 kcal of heat is added to 1.700 L of oxygen in a cylinder at constant pressure of 1.00 atm, the volume increases to 2.100 L. Calculate the total energy change for this process. Pay careful attention to units.

delta E = q + w

I would convert 1.000 kcal to joules and substitute for q. w = -p*delta V. I would use 101.325 kPa for 1 atm pressure and substitute V2-V1 for delta V (in liters).

i got .990 k cal

is that right?

That's my answer in kcal.

To calculate the total energy change for this process, we need to use the equation relating energy change to heat and work. The equation is:

ΔE = q - w

Where:
ΔE is the total energy change,
q is the heat added, and
w is the work done.

In this case, we are given that 1.000 kcal (kilocalories) of heat is added. However, it is essential to convert this value to joules since the unit of work is joules. The conversion factor is 1 kcal = 4184 J.

So, the heat added (q) can be calculated as follows:

q = (1.000 kcal) x (4184 J/kcal)
q = 4184 J

Now, to determine the work done (w), we need to recall that work is given by the equation:

w = P∆V

Where:
w is the work done,
P is the pressure, and
∆V is the change in volume.

In this case, we are given that the initial volume is 1.700 L, and it increases to 2.100 L. Thus,

∆V = 2.100 L - 1.700 L
∆V = 0.400 L

However, it is crucial to convert the volume change to the SI unit of liters to calculate the work correctly. The conversion factor is 1 L = 0.001 m^3.

So, the volume change (∆V) can be calculated as follows:

∆V = (0.400 L) x (0.001 m^3/L)
∆V = 0.0004 m^3

Keep in mind that pressure is given in atm, and we need to convert it to the SI unit of Pascals (Pa). The conversion factor is 1 atm = 101325 Pa.

So, the pressure (P) can be calculated as follows:

P = (1.00 atm) x (101325 Pa/atm)
P = 101325 Pa

Now, we can calculate the work done (w):

w = (101325 Pa) x (0.0004 m^3)
w = 40.53 J

Finally, we can calculate the total energy change (ΔE) using the equation:

ΔE = q - w
ΔE = 4184 J - 40.53 J
ΔE = 4144.47 J

Therefore, the total energy change for this process is 4144.47 joules.