Question

The chamber is a box with a fixed height and length both of 4.3 nm
. Using the widths 6.0, 8.0, 10.0, and 12.0 nm
, calculate the volume of the container. Then determine the reciprocal (inverse) of the pressure ( 1/P
) using your data in Part C.

Width of box
( nm
) 6.0 8.0 10.0 12.0
Pressure
( atm
) 19.3 14.5 11.6 9.8
Plot the graph of the volume ( V
) versus the reciprocal (inverse) of pressure ( 1/P
).

Answer 1

To calculate the volume of the container, we use the formula V = lwh, where l = 4.3 nm, w varies, and h = 4.3 nm:
Volume when w = 6.0 nm: V = (4.3 nm)(6.0 nm)(4.3 nm) = 110.088 nm^3
Volume when w = 8.0 nm: V = (4.3 nm)(8.0 nm)(4.3 nm) = 147.2 nm^3
Volume when w = 10.0 nm: V = (4.3 nm)(10.0 nm)(4.3 nm) = 183.05 nm^3
Volume when w = 12.0 nm: V = (4.3 nm)(12.0 nm)(4.3 nm) = 219.6 nm^3

Next, we calculate the reciprocal of pressure (1/P):
Reciprocal of pressure when P = 19.3 atm: 1/P = 1/19.3 = 0.0518 atm^-1
Reciprocal of pressure when P = 14.5 atm: 1/P = 1/14.5 = 0.0690 atm^-1
Reciprocal of pressure when P = 11.6 atm: 1/P = 1/11.6 = 0.0862 atm^-1
Reciprocal of pressure when P = 9.8 atm: 1/P = 1/9.8 = 0.102 atm^-1

Lastly, we can plot the graph of V versus 1/P to visualize the relationship between volume and the reciprocal of pressure.