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The gas laws describe the behavior of gases under specific conditions of temperature, pressure, and volume. Three gas laws show...Question
The gas laws describe the behavior of gases under specific conditions of temperature, pressure, and volume. Three gas laws show the relationship between two variables when all others are held constant: Boyle’s law (pressure and volume are inversely proportional), Charles’s law (volume and temperature are directly proportional), and Gay-Lussac’s law (temperature and pressure are directly proportional).
The three laws can be combined into one law, called the combined gas law.
pressure times volume over temperature under conditions 1 equals pressure times volume over temperature under conditions 2
A balloon has a volume of 2.55 L, a pressure of 1.15 atm, and a temperature of 25 °C. What is the new pressure, if the new volume is 3.15 L and the new temperature is 45 °C?
The three laws can be combined into one law, called the combined gas law.
pressure times volume over temperature under conditions 1 equals pressure times volume over temperature under conditions 2
A balloon has a volume of 2.55 L, a pressure of 1.15 atm, and a temperature of 25 °C. What is the new pressure, if the new volume is 3.15 L and the new temperature is 45 °C?
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GPT 3.5
To solve this problem using the combined gas law, we can set up the equation as follows:
\(P_1V_1/T_1 = P_2V_2/T_2\)
Plugging in the values:
\(1.15 atm * 2.55 L / (25 + 273) K = P_2 * 3.15 L / (45 + 273) K\)
\(0.404 atm = P_2 * 3.15 L / 318 K\)
\(P_2 = 0.404 atm * 318 K / 3.15 L\)
\(P_2 = 40.82 atm\)
So, the new pressure in the balloon is 40.82 atm.
\(P_1V_1/T_1 = P_2V_2/T_2\)
Plugging in the values:
\(1.15 atm * 2.55 L / (25 + 273) K = P_2 * 3.15 L / (45 + 273) K\)
\(0.404 atm = P_2 * 3.15 L / 318 K\)
\(P_2 = 0.404 atm * 318 K / 3.15 L\)
\(P_2 = 40.82 atm\)
So, the new pressure in the balloon is 40.82 atm.
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