Question
A sample of sulfur dioxide gas has a volume of 0.871 L and a temperature of 315 K, under a constant pressure. What is the new volume, if the temperature is increased to 385 K?
Answers
GPT 3.5
To solve this problem, we can use the combined gas law which states:
(V1 / T1) = (V2 / T2)
Where:
V1 = initial volume (0.871 L)
T1 = initial temperature (315 K)
V2 = final volume (unknown)
T2 = final temperature (385 K)
Plugging in the values:
(0.871 L / 315 K) = (V2 / 385 K)
Cross multiplying:
0.871 * 385 = V2 * 315
V2 = (0.871 * 385) / 315
V2 = 1.067 L
Therefore, the new volume of the sulfur dioxide gas when the temperature is increased to 385 K is 1.067 L.
(V1 / T1) = (V2 / T2)
Where:
V1 = initial volume (0.871 L)
T1 = initial temperature (315 K)
V2 = final volume (unknown)
T2 = final temperature (385 K)
Plugging in the values:
(0.871 L / 315 K) = (V2 / 385 K)
Cross multiplying:
0.871 * 385 = V2 * 315
V2 = (0.871 * 385) / 315
V2 = 1.067 L
Therefore, the new volume of the sulfur dioxide gas when the temperature is increased to 385 K is 1.067 L.