What is the value of in so that the expression x squared plus 11x + n is a perfect square trinomial

Answer 1

To find the value of n so that the expression x^2 + 11x + n is a perfect square trinomial, we can use the formula for a perfect square trinomial:

(x + a)^2 = x^2 + 2ax + a^2

Comparing this formula to the given expression x^2 + 11x + n, we see that 2a = 11 and a^2 = n.

Since 2a = 11, we can solve for a by dividing 11 by 2:

2a = 11
a = 11/2
a = 5.5

Now that we have found the value of a, we can find the value of n by squaring a:

n = a^2
n = (5.5)^2
n = 30.25

Therefore, the value of n that makes the expression x^2 + 11x + n a perfect square trinomial is 30.25.