Asked by Fiona
A 190 g particle is released from rest at point A inside a smooth hemispherical bowl of radius 25.0 cm.
Calculate the gravitational potential energy at A
also, how do you find kinetic energy if you aren't given velocity?
please help me! i would really appreciate it
Calculate the gravitational potential energy at A
also, how do you find kinetic energy if you aren't given velocity?
please help me! i would really appreciate it
Answers
Answered by
drwls
The potential energy depends upon the height h above the bottom of the hemisphere. You have not said where point A is, so I cannot tell you the value of potential energy.
Its value is P.E. = M g h.
If you know the angle from the vertical at point A, measured from the center of curvature of the bowl, then
h = R(1 - cos A)
As it slides down the bowl, it gains kinetic energy (K.E.) equal to the decrease in P.E.
Its value is P.E. = M g h.
If you know the angle from the vertical at point A, measured from the center of curvature of the bowl, then
h = R(1 - cos A)
As it slides down the bowl, it gains kinetic energy (K.E.) equal to the decrease in P.E.
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