Solve the system of equations.

3x−4y=40
5x−5y=55(1 point)
Responses

1 answer

To solve the system of equations, we can first rewrite the equations in standard form (Ax + By = C):

1) 3x - 4y = 40
2) 5x - 5y = 55

Next, we can solve the system using substitution or elimination method. Let's use the elimination method:

Multiply the first equation by 5 and the second equation by 3 to make the coefficients of y the same:

1) 15x - 20y = 200
2) 15x - 15y = 165

Now subtract the second equation from the first:

-5y = 35
y = -7

Now substitute the value of y back into one of the equations to solve for x:

3x - 4(-7) = 40
3x + 28 = 40
3x = 12
x = 4

Therefore, the solution to the system of equations is x = 4 and y = -7.