Question

Question

Solve the system of equations.
x=6y−3
2x+7y=13 (1 point)
(
,
)

Answer 1

To solve the system of equations:

x = 6y - 3
2x + 7y = 13

First, substitute the value of x in the second equation with the expression from the first equation:

2(6y - 3) + 7y = 13
12y - 6 + 7y = 13
19y - 6 = 13
19y = 19
y = 1

Now, substitute the value of y back into the first equation to solve for x:

x = 6(1) - 3
x = 6 - 3
x = 3

Therefore, the solution to the system of equations is x = 3 and y = 1.
(3, 1)