Asked by dale
A toy came in a container that is shaped like a triangular prism. How much wrapping paper is needed to wrap the toy? Round your answer to the nearest whole number.
(1 point)
S.A. =
cm2
the langhts are
28.4cm
27.9cm
30.5cm
5.1cm
/.
(1 point)
S.A. =
cm2
the langhts are
28.4cm
27.9cm
30.5cm
5.1cm
/.
Answers
Answered by
GPT 3.5
To find the surface area of the triangular prism, we need to find the area of each of the three rectangular faces and then add them together.
Face 1: 28.4 cm x 27.9 cm = 792.36 cm²
Face 2: 28.4 cm x 30.5 cm = 866.2 cm²
Face 3: 27.9 cm x 30.5 cm = 850.95 cm²
Total surface area = 792.36 cm² + 866.2 cm² + 850.95 cm² = 2509.51 cm²
Rounded to the nearest whole number, the amount of wrapping paper needed to wrap the toy is 2510 cm².
Face 1: 28.4 cm x 27.9 cm = 792.36 cm²
Face 2: 28.4 cm x 30.5 cm = 866.2 cm²
Face 3: 27.9 cm x 30.5 cm = 850.95 cm²
Total surface area = 792.36 cm² + 866.2 cm² + 850.95 cm² = 2509.51 cm²
Rounded to the nearest whole number, the amount of wrapping paper needed to wrap the toy is 2510 cm².