To find the perimeter of the outside of the house, we need to add up the lengths of all the sides of the shape formed by the coordinates A, B, C, and D.
Let's start by finding the length of side AB:
AB = |y2 - y1| = |-6 - 12| = 18 yards
Next, let's find the length of side BC:
BC = |x2 - x1| = |-4 - 6| = 10 yards
Then, the length of side CD:
CD = |y2 - y1| = |12 - (-6)| = 18 yards
Finally, the length of side DA:
DA = |x2 - x1| = |6 - (-4)| = 10 yards
Now, we can add up all the side lengths to get the perimeter:
Perimeter = AB + BC + CD + DA
Perimeter = 18 + 10 + 18 + 10 = 56 yards
Therefore, the perimeter of the outside of the house is 56 yards.
A contractor is building a new house. She creates a map with the coordinates A(6,12)
, B(6,−6)
, C(−4,−6)
, and D(−4,12)
. Each unit on the coordinate plane represents 1 yard. What is the perimeter of the outside of the house?
1 answer