Solve the system of equations

Question

3X minus 4Y equals 40
5X minus 5Y equals 55

Answer 1

To solve this system of equations, we can use the method of substitution or elimination.

Let's use the method of elimination by multiplying the first equation by 5 and the second equation by 3 to make the coefficients of X the same:

15X - 20Y = 200
15X - 15Y = 165

Now we can subtract the second equation from the first:

15X - 20Y - 15X + 15Y = 200 - 165
-5Y = 35
Y = -7

Now that we have found the value of Y, we can substitute it back into one of the original equations to solve for X:

3X - 4(-7) = 40
3X + 28 = 40
3X = 12
X = 4

Therefore, the solution to the system of equations is X = 4 and Y = -7.