To solve the system of equations, we will substitute the values of X and Y for each of the given options and see if they satisfy both equations.
1. For (5, -2):
First equation: -3(5) - 4(-2) = -23
-15 + 8 = -23
-7 ≠ -23
Second equation: 2(5) - 5(-2) = 5
10 + 10 = 5
20 ≠ 5
(5, -2) does not satisfy both equations.
2. For (-5, 2):
First equation: -3(-5) - 4(2) = -23
15 - 8 = -23
7 ≠ -23
Second equation: 2(-5) - 5(2) = 5
-10 - 10 = 5
-20 ≠ 5
(-5, 2) does not satisfy both equations.
3. For (5, 2):
First equation: -3(5) - 4(2) = -23
-15 - 8 = -23
-23 = -23
Second equation: 2(5) - 5(2) = 5
10 - 10 = 5
0 ≠ 5
(5, 2) does not satisfy both equations.
4. For (-5, -2):
First equation: -3(-5) - 4(-2) = -23
15 + 8 = -23
23 ≠ -23
Second equation: 2(-5) - 5(-2) = 5
-10 + 10 = 5
0 ≠ 5
(-5, -2) does not satisfy both equations.
Therefore, none of the given options are solutions to the system of equations.
Solve the system of two linear equations
Negative 3X minus 4Y equals -23
2X minus 5Y equals five
(5,-2)
(-5,2)
(5,2)
(-5,-2)
1 answer