To solve this system of equations, we can use the method of elimination.
First, let's add the two equations together to eliminate the variable Y:
(6X - 5Y) + (3X + 5Y) = 27 + 36
9X = 63
X = 7
Now that we have found the value of X, we can substitute it back into one of the original equations to solve for Y:
6(7) - 5Y = 27
42 - 5Y = 27
-5Y = -15
Y = 3
Therefore, the solution to the system of equations is X = 7 and Y = 3.
Solve the system of equations
6X minus 5Y equals 27
3X plus 5Y equals 36
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