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In a family with two children, what are the probabilities of the following outcomes, assuming that the birth of boys and girls...Asked by Punkie
In a family with two children, what are the probabilities of the following outcomes, assuming that the birth of boys and girls is equally likely?
a. Both are boys.
b. The first is a girl and the second a boy.
c. Neither is a girl.
d. At least one is a girl.
I was wondering about the formula....
is a. P(probability) = 1/2(boy) + 1/2(boy)
P = 1/2 + 1/2
so P = 2/2
to me this doesn't seem right
a. Both are boys.
b. The first is a girl and the second a boy.
c. Neither is a girl.
d. At least one is a girl.
I was wondering about the formula....
is a. P(probability) = 1/2(boy) + 1/2(boy)
P = 1/2 + 1/2
so P = 2/2
to me this doesn't seem right
Answers
Answered by
bobpursley
A) PR(B,B)=Pr(b)*Pr(b)=1/2*1/2
B) Pr(g)Pr(b)=1/2*1/2
C) you can get at least one girl these ways:
gb
bg
gg
Pr(at least one g)= 1/2*1/2*3
B) Pr(g)Pr(b)=1/2*1/2
C) you can get at least one girl these ways:
gb
bg
gg
Pr(at least one g)= 1/2*1/2*3
Answered by
Punkie
Thank you for answering my question.
Why do you multiply the probability of both boys, girl and boy, etc?
Why do you multiply the probability of both boys, girl and boy, etc?
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