Question

How many O2 atoms are in 0.25 miles of Ca(NO3)

Answer 1

To determine the number of O2 atoms in 0.25 moles of Ca(NO3)2, we need to first find the molar mass of Ca(NO3)2 and then calculate the number of moles of O2 atoms in 0.25 moles of the compound.

The molar mass of Ca(NO3)2:
Ca = 40.08 g/mol
N = 14.01 g/mol
O = 16 g/mol

2(16) + 6(16 + 3(14.01)) = 164.09 g/mol

0.25 moles of Ca(NO3)2 is equal to:
0.25 moles x 164.09 g/mol = 41.0225 grams

Now we calculate the number of moles of O2 atoms in 41.0225 grams of Ca(NO3)2 and convert it to atoms:

1 mole of O2 has 6.022 x 10^23 atoms

41.0225 grams / 32 g/mol = 1.2814 moles

1.2814 moles x 6.022 x 10^23 atoms/mole = 7.717 x 10^23 atoms

Therefore, there are approximately 7.717 x 10^23 O2 atoms in 0.25 miles of Ca(NO3)2.