Question
A hydrated salt of formula MSO4•SH2O contain 45.3% by mass of the water of crystalization.calculate the value of x(M=56,S=32,O=16,H=1)
What is x
What is x
Answers
GPT 3.5
To calculate the value of x, we first need to determine the molecular weight of the hydrated salt and the molecular weight of the water of hydration.
Molecular weight of MSO4•SH2O:
Molecular weight of M = 56
Molecular weight of S = 32
Molecular weight of O = 16
Molecular weight of H = 1
Molecular weight of water (H2O) = 2(1) + 16 = 18
Total molecular weight of MSO4•SH2O:
56 + 32 + 4(16) + 18 = 56 + 32 + 64 + 18 = 170
Now, calculate the mass of water in the hydrated salt:
Let's assume the mass of the hydrated salt is 100g.
The mass of water in the hydrated salt is 45.3% of its mass, which is 45.3g.
Now, let's calculate the amount of MSO4 in 100g of hydrated salt:
Mass of MSO4 = 100g - 45.3g = 54.7g
Calculate the moles of MSO4:
54.7g / 170g/mol = 0.3217 mol
From the formula MSO4•xH2O, we can see that there is one S atom in the formula, therefore the value of x is 1.
Molecular weight of MSO4•SH2O:
Molecular weight of M = 56
Molecular weight of S = 32
Molecular weight of O = 16
Molecular weight of H = 1
Molecular weight of water (H2O) = 2(1) + 16 = 18
Total molecular weight of MSO4•SH2O:
56 + 32 + 4(16) + 18 = 56 + 32 + 64 + 18 = 170
Now, calculate the mass of water in the hydrated salt:
Let's assume the mass of the hydrated salt is 100g.
The mass of water in the hydrated salt is 45.3% of its mass, which is 45.3g.
Now, let's calculate the amount of MSO4 in 100g of hydrated salt:
Mass of MSO4 = 100g - 45.3g = 54.7g
Calculate the moles of MSO4:
54.7g / 170g/mol = 0.3217 mol
From the formula MSO4•xH2O, we can see that there is one S atom in the formula, therefore the value of x is 1.