Asked by Izzy

Write the slope intercept form of an equation for the line that passes through (5,3) and is parallel to x+3y=6 . Please help me solve!!!!!!!!!!
Answered by bobpursley
put the given equation into slope intercept form.

y=-1/3 x +6
so the slope is -1/3

Now, your new line will be of the form

y=mx+b. To be parallel, it must have a slope of -1/3.
y=-1/3 x + b
Now put the point on the line (5,3), and solve for b, and you have it, both m, and b.
Answered by Izzy
How would you solve for b?
Answered by bobpursley
put y=3, x=5 into
y=-1/3 x+ b
solve for b.
Answered by Izzy
ok thank you!! I got y=1/3x+4/5
Answered by bobpursley
well that is not right at all.

y=-1/3 x + b
b= y+1/3 x=3+5/3= 4 2/3 which is not 4/5
Did I make an error?
Answered by Izzy
I Have no idea...I put in the #s so that it was 3=1/3(5)+b
Answered by Izzy
I see what I did wrong, forgot the negative sign.