Question

Use the image to answer the question.

A coordinate plane plots temperature in Celsius for different days. The x-axis labeled day, and the y-axis labeled temperature degree Celcius, both range from negative 5 to 5 in increments of 1. Six unlabeled points are plotted. Quadrant 1 is labeled with left parenthesis positive sign comma positive sign right parenthesis. Quadrant 2 is labeled with left parenthesis negative sign comma positive sign right parenthesis. Quadrant 3 is labeled with left parenthesis negative sign comma negative sign right parenthesis. Quadrant 4 is labeled with left parenthesis positive sign comma negative sign right parenthesis. Points are plotted at left parenthesis 2 comma 2 right parenthesis; left parenthesis negative 4 comma 4 right parenthesis, left parenthesis negative 3 comma 0 right parenthesis; left parenthesis negative 2 comma negative 2 right parenthesis; left parenthesis zero comma zero right parenthesis; left parenthesis 4 comma negative 1 right parenthesis.

Alex is tracking temperatures. Today the temperature was 0° Celsius, which is represented by the point (0, 0) . If the temperature yesterday was right in between today’s temperature and the temperature two days ago, what was the temperature yesterday?

(1 point)

7 answers

The temperature two days ago is represented by the point (2, 2) and today's temperature is represented by the point (0, 0). The temperature halfway between these two points would be the midpoint of the line segment connecting them.

To find the midpoint, we can use the formula:
Midpoint = ( (x1 + x2) / 2 , (y1 + y2) / 2 )

Substitute in the coordinates:
Midpoint = ( (0 + 2) / 2 , (0 + 2) / 2 )
Midpoint = (1, 1)

Therefore, the temperature yesterday, represented by (1,1) is 1° Celsius.
Are you sure?
Let's try to find the midpoint of the points (0,0) and (2,2) again:

Midpoint = ((0 + 2) / 2, (0 + 2) / 2)
Midpoint = (2 / 2, 2 / 2)
Midpoint = (1, 1)

So, the coordinates for the midpoint is indeed (1, 1), and therefore the temperature yesterday was 1°C.
wrong
Apologies for the incorrect response earlier. Let's try to find the correct midpoint again:

Midpoint = ((0 + 2) / 2, (0 + 2) / 2)
Midpoint = (2 / 2, 2 / 2)
Midpoint = (1, 1)

Therefore, the temperature yesterday was indeed 1°C.
-1 °C
Apologies for the mistake in my previous responses.

Given that today's temperature is 0°C and the temperature two days ago is 2°C, the correct midpoint is calculated as follows:

Midpoint = ((0 + 2) / 2, (0 + 2) / 2)
Midpoint = (2 / 2, 2 / 2)
Midpoint = (1, 1)

The coordinates for the midpoint are (1, 1), which corresponds to 1°C. Therefore, the temperature yesterday, which is right in between today's temperature and the temperature two days ago, is 1°C.