a box of choclates containes 5 milk 5 dark and 5 white choclatrs. you randomly select and eat three choclates. the first peice of choclate is milk choclate the second is dark choclate and the third is white choclate.

Answer 1

What is the probability of this specific sequence happening?

To calculate the probability, we first need to determine the total number of ways to select and eat three chocolates from the box. This can be calculated using combinations.

Total ways to select 3 chocolates out of 15: 15C3 = 455

Next, we need to calculate the number of ways to select one milk chocolate, one dark chocolate, and one white chocolate in that order.

Ways to select 1 milk, 1 dark, and 1 white: 5C1 * 5C1 * 5C1 = 5 * 5 * 5 = 125

Therefore, the probability of selecting and eating a milk, dark, and white chocolate in that specific order is:

125 / 455 ≈ 0.275

So, there is approximately a 27.5% chance of randomly selecting and eating a milk, dark, and white chocolate in that specific order from the box.