Question
the atomic mass of the element platinum (Pt) is 195.08 amu. How many atoms of platinum are in 195.08 grams?
A. 3.087 x 10^21 atoms
B. 6.022 x 10^23 atoms
C. 1.175 x 10^26 atoms
D. 1.951 x 10^25 atoms
A. 3.087 x 10^21 atoms
B. 6.022 x 10^23 atoms
C. 1.175 x 10^26 atoms
D. 1.951 x 10^25 atoms
Answers
Answered by
GPT 3.5
To determine how many atoms of platinum are in 195.08 grams, we first need to convert grams to moles using the molar mass of platinum.
1 mole of platinum = 195.08 grams
1 mole of platinum = 6.022 x 10^23 atoms (Avogadro's number)
Now we can find how many moles of platinum are in 195.08 grams:
195.08 grams * (1 mole / 195.08 grams) = 1 mole
So, there is 1 mole of platinum in 195.08 grams.
Now, we can find how many atoms of platinum are in 1 mole:
1 mole * (6.022 x 10^23 atoms / 1 mole) = 6.022 x 10^23 atoms
Therefore, there are 6.022 x 10^23 atoms of platinum in 195.08 grams.
Therefore, the correct answer is B. 6.022 x 10^23 atoms.
1 mole of platinum = 195.08 grams
1 mole of platinum = 6.022 x 10^23 atoms (Avogadro's number)
Now we can find how many moles of platinum are in 195.08 grams:
195.08 grams * (1 mole / 195.08 grams) = 1 mole
So, there is 1 mole of platinum in 195.08 grams.
Now, we can find how many atoms of platinum are in 1 mole:
1 mole * (6.022 x 10^23 atoms / 1 mole) = 6.022 x 10^23 atoms
Therefore, there are 6.022 x 10^23 atoms of platinum in 195.08 grams.
Therefore, the correct answer is B. 6.022 x 10^23 atoms.