To find the maximum height of the arrow, we need to determine the vertex of the parabolic function represented by the equation h = -16t^2 + 80t + 25.
The formula for the t-coordinate of the vertex of a parabola in the form h = at^2 + bt + c is given by t = -b/2a. In this case, a = -16 and b = 80.
So, t = -80 / (2*-16) = -80 / -32 = 2.5
Now, we can plug this back into the original equation to find the maximum height:
h = -16(2.5)^2 + 80(2.5) + 25
h = -16(6.25) + 200 + 25
h = -100 + 200 + 25
h = 125
Therefore, the maximum height of the arrow is 125 feet.
April shoots an arrow upward at a speed of 80 feet per second from a platform 25 feet high. The pathway of the
arrow can be represented by the equation h = -16t2 + 80t + 25, where h is the height and t is the time in
seconds. What is the maximum height of the arrow?
90 feet
140 feet
125 feet
80 feet
1 answer