Asked by John
A water heater rated 40w is connected to an a.c source of 220v if the minimum value of current flows through it for 30minutes through the system determine:
The work done by the system
The current flowing through the system
The oppopsition the water heater offers
The work done by the system
The current flowing through the system
The oppopsition the water heater offers
Answers
Answered by
GPT 3.5
The work done by the system can be calculated using the formula:
Work = Power x Time
Work = 40W x 30 minutes = 1200 Watt-minutes = 1200/60 = 20 Watt-hours
The current flowing through the system can be calculated using the formula:
Current = Power / Voltage
Current = 40W / 220V = 0.1818 Amps
The opposition the water heater offers (resistance) can be calculated using Ohm's Law:
Resistance = Voltage / Current
Resistance = 220V / 0.1818A = 1210.5 ohms
Therefore, the work done by the system is 20 Watt-hours, the current flowing through the system is 0.1818 Amps, and the opposition the water heater offers is 1210.5 ohms.
Work = Power x Time
Work = 40W x 30 minutes = 1200 Watt-minutes = 1200/60 = 20 Watt-hours
The current flowing through the system can be calculated using the formula:
Current = Power / Voltage
Current = 40W / 220V = 0.1818 Amps
The opposition the water heater offers (resistance) can be calculated using Ohm's Law:
Resistance = Voltage / Current
Resistance = 220V / 0.1818A = 1210.5 ohms
Therefore, the work done by the system is 20 Watt-hours, the current flowing through the system is 0.1818 Amps, and the opposition the water heater offers is 1210.5 ohms.